I would bet that anyone that has any college (or other) class experience has had a poor instructor. You are taking a class and you have to do what it takes to do the work or drop the class or fail. The old post you saw was really a mistake and, if you read it, was only posted becuase the poster was short on time. Ok, As it has been stated - nobody is going to do it for you. My problem is that i would like if someone have solution to send me on my e-mail becouse i really dont have a clue about this and i need it ergantAndrejj, Play with that and see what you come up with.
#Silo logix pro full#
Maybe something to keep the motor running after the full light goes off? With the logixpro you can run single scan to check things out. You need to figure a way to keep that motor running until the next bottle is in place. I would assume from your logic that it is not properly moving the next bottle into position. Ok, now to address your problem - but you didnt let us know what the problem is. Our focus is on readability of the logic and making it easy for the next poor sapp that has to follow our logic.
#Silo logix pro code#
We are not computer scientists attempting to optimize our code for size (after Microsoft I am not sure anyone is any more). Also, I believe a well written program is not a concise, compact program. So just because it didnt have one when you put it in doesnt mean it wont have one in a year. The nature of PLC programs are that they can be changed.
Anything actuated by a lamp will then be actuated by the test button. Many times lamps will have lamp test buttons. First I would stay away from using indicator lamp outputs to actuate other logic in your program. Let me give you some pointers for the real world. Note: The stop switch was omitted to simplify the development.Let me say that I am not familiar enough with the routine you are working on to say a lot about it. O:2/0 closes (Motor starts turning forward) 9. O:2/1 opens (Motor stops turning in reverse) 8b. O:2/1 closes (Motor is turning in reverse direction) 7. I:1/0 is closed I:1/1 is open Start O:2/0 closes (Motor is turning in forward direction) Open I:1/0 to indicate that the box is departing the West end (The NO switch opens) Close I:1/1 to indicate box arriving East end 6a. Rung 4 is the implementation of the reverse equation. Rung 1 is A, Rung 3 is B, rung 2 is (Anot)(Bnot), and O:24 in rung 1 is not(Anot Bnot). If we call rung 1 = A and the third element = B then A + B = not(Anot Bnot). Their output, O:2/4 is applied to rung zero. Rungs 2 and 3, combined are the DeMorganized representation of the third member of the forward equation, ored to rung 1. Rung 1 is the implementation of the first two members of the forward equation. (The negated function provides the needed continuity in the rung). We want reverse operation only when the switch is in its true, open state.), or when (O:2/1)(I:1/0not) The motor is running in reverse and the West limit switch is open. O:2/1 is true (motor runs reverse) when I:1/1 + The West limit switch is open (Remember it is NO. The East limit switch had to be included in all the elements to prevent reverse action when moving forward. The negated function shows continuity when the switch is open), or when (O:2/0)(I:1/1not) + The motor is running forward and the East limit switch is not closed (hold function), or when (O:2/1not)(I:1/0) The motor is not running in reverse and the West limit switch is closed (reset function). Logic equation: O:2/0 = (I:1/4)(I:1/1not) + (O:2/0)(I:1/1not) + (O:2/1not)(I:1/0) O:2/1 = I:1/1 + (O:2/1)(I:1/0not) In words: O:2/0 is true (motor runs forward) when (I:1/4)(I:1/1not) + The start switch is open and the East limit switch is not closed (remember that the East limit switch is NO.
#Silo logix pro simulator#
Outputs: O:2/0, Forward direction output O:2/1, Reverse direction output Auxiliary logic inputs and outputs used to counteract the simulator limitations: O:2/2 O:2/3 O:2/4 West-end limit switch East-end limit switch Start switch Stop switch Implement the solution using the LogixPro simulator.
The stop switch is momentary, normally closed.
Assume that the limiting positions are signaled by two normally open limit switches and the start switch is of the momentary, normally open type. Then it reverses direction to bring the box back to its starting position and the cycle continues until the Stop switch is pressed. When the switch is pressed, the motor rotates causing the conveyor to move one way. Assume that the conveyor is activated by a motor. Once the start switch is pressed, the box moves back and forth between two limiting positions. In other words, the box is at the West end. Forward-Reverse Motor Simulation in TLP LogixPro Problem: A box is at the West end of the conveyor A start switch is pressed The box moves to the East end.
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